
 a) Write the chemical equation :

    a Ba**(+2) + b IO[3]**(-) -> c Ba (IO[3])[2]

   
 b) Write the list of the chemical elements.
 
         Ba :   a           =  c   |a = c -> a - c = 0 -> 0 = 0                       
         IO :  3b           = 6c   | This line is not useful.             
        +/- : +2a - b       =  0           


 c) Rewrite the list.
 
         Ba :                    
         IO :  3b - 6c      =  0                 
        +/- : +2a -  b      =  0           


 d) Write the list of the chemical elements in a matrix :

            a     b     c    
            --------------
     Ba :            
     IO :        3b   -6c   = 0
    +/- : +2a    -b         = 0


 e) Complete the matrix :

           a     b     c    
           --------------
     Ba :  
     IO :  0/1   3/1  -6/1  0/1  
    +/- :  2/1  -1/1   0/1  0/1  


  f) This system has 2 rows, and three values to find.
     ( a, b, c).
     If the system is consistent, it will have many solutions.

         1,1,  0,1,   0,1,  1,1,    (a = 1/1)  
         0,1,  3,1,  -6,1,  0,1,
         2,1, -1,1,   0,1,  0,1,   

     To find a solution, I must give a value, to a coefficient.
     I have chosen to write a = 1/1.





